# Learn Python – How to reverse a number in Python- Basic and advance

It is the most asked programming query in the interview. We can reverse the integer range in Python using the special methods.

Here we will write the software which takes enter quantity and reversed the same. Let’s apprehend the following methods of reversing the integer number.

Using while loop

Using recursion

Reverse a number using Python while loop

First, we apprehend the algorithm of this program. It will make easy to apprehend the application logic. Once you get the logic, you can write the application in any language, not only Python.

Algorithm

``````Input Integer:  number
(1) Initialize variable revs_number = 0
(2) Loop while number > 0
(a) Multiply revs_number by 10 and add remainder of number
divide by 10 to revs_number
revs_number = revs_number*10 + number%10;
(b) Divide num by 10
(3) Return revs_number
``````

Let’s implement the above algorithm in program.

Program

``````# Ask for enter the number from the use
number = int(input("Enter the integer number: "))

# Initiate value to null
revs_number = 0

# reverse the integer number using the while loop

while (number > 0):
# Logic
remainder = number % 10
revs_number = (revs_number * 10) + remainder
number = number // 10

# Display the result
print("The reverse number is : {}".format(revs_number))
``````

Output:

``````Enter the integer number: 12345
The reverse number is: 54321``````

Explanation –

Let’s understand this program step by step.

We initialed a wide variety variable for person enter and variable revs_number initial value to null.

First Iteration

Reminder = number %10 Reminder = 12345%10 = 5 Reverse = Reverse *10 + Reminder Initial price of revs_number is null Reverse = zero * 10 + 5 = zero + 5 = 5 Number = Number //10 Number = 1234 //10 = 1234 // Now loop will iterate on this number.

Second Iteration

Now the variety is 123, and the revs_number is 5. The while exams its circumstance and executes for the subsequent iteration.

Reminder = Number percent 10 Reminder = 1234 % 10 = 4 Reverse = Reverse *10+ Reminder = 5 * 10 + 4 Reverse = 50 + 4 = 54 Number = Number //10 = 12345 //10 Number = 123

Third Iteration

From the Second Iteration, the values of each Number and Reverse have been modified as: range = 123 and revs_number = 54

Reminder = Number %10 Reminder = 123%10 = 3 Reverse = Reverse *10+ Reminder = 54 * 10 + 3 Reverse = 540 + three = 543 Number = Number //10 = 123//10 Number = 12

Fourth Iteration

The modified quantity is 12 and the revs_number is 543: Now whilst executes again.

Reminder = Number %10 Reminder = 12 %10 = 2 Reverse = Reverse *10+ Reminder = 543 * 10 + 2 Reverse = 5430 + two = 5432 Number = Number //10 = 12//10 Number = 1

Fifth Iteration

Reminder = Number %10 Reminder = 1 %1 zero = 1 Reverse = Reverse *10+ Reminder = 5432 * 10 + 1 Reverse = 54320 + 1 = 54321

while loop is terminated due to the fact if discovered the false as a Boolean result.

You can enter the unique variety and test the result.

Reverse a Number Using Recursion

Let’s understand the following example.

``````num = int(input("Enter the number: "))
revr_num = 0    # initial value is 0. It will hold the reversed number
def recur_reverse(num):
global revr_num   # We can use it out of the function
if (num > 0):
Reminder = num % 10
revr_num = (revr_num * 10) + Reminder
recur_reverse(num // 10)
return revr_num

revr_num = recur_reverse(num)
print("n Reverse of entered number is = %d" % revr_num)
``````

Output:

``````Enter the number: 5426
The Reverse of entered number is = 6245``````

Logic is identical in each programs. Once you understand the logic, it will handy to do it by own.