In this tutorial, we will study how to get the permutation and aggregate of a given data the usage of Python. We will use Python in-built package deal to discover the permutation and aggregate of a given number.

Permutation and aggregate are an vital part in mathematics. Python gives the itertools library that has the in-built features to calculate permutation and combination.

## Importing the Required library

To calculate the permutation and combination, we want to import the itertools library. We can import it the use of the under command.

```
import itertools
```

The above announcement will import the itertools library and types a pathway to its function.

Now, we want to create the list of a sequence as an input. This listing of input will return the tuple which consists of permutation and combination. We can also set the size of the permutation and combination.

## Permutation

A permutation is an arrangement of a set where order does matter. Python itertools module provide inbuilt permutation() technique to locate the permutation. Let’s apprehend the following example.

Example –

```
from itertools import permutations
seq = permutations(['1','2','3'])
print(seq)
for p in list(seq):
print(p)
```

Output:

```
('1', '2', '3')
('1', '3', '2')
('2', '1', '3')
('2', '3', '1')
('3', '1', '2')
('3', '2', '1')
```

In the above code, we have imported the itertools module. We known as the permutation() approach which takes string as an argument and provides an itertools object. It is essential to use for loop to get the every permutation.

Let’s take two sets of permutation.

Example – 2

```
from itertools import permutations
seq = permutations(['A','B'])
for p in list(seq):
print(p)
```

Output:

```
('A', 'B')
('A', 'C')
('B', 'C')
```

Example – 3

```
from itertools import permutations
list1 = [1, 2, 3, 4]
seq = permutations(list1)
print(seq)
for p in list(seq):
print(p)
```

Output:

```
(1, 2, 3, 4)
(1, 2, 4, 3)
(1, 3, 2, 4)
(1, 3, 4, 2)
(1, 4, 2, 3)
(1, 4, 3, 2)
(2, 1, 3, 4)
(2, 1, 4, 3)
(2, 3, 1, 4)
(2, 3, 4, 1)
(2, 4, 1, 3)
(2, 4, 3, 1)
(3, 1, 2, 4)
(3, 1, 4, 2)
(3, 2, 1, 4)
(3, 2, 4, 1)
(3, 4, 1, 2)
(3, 4, 2, 1)
(4, 1, 2, 3)
(4, 1, 3, 2)
(4, 2, 1, 3)
(4, 2, 3, 1)
(4, 3, 1, 2)
(4, 3, 2, 1)
```

In the above code, we have got the aggregate of the more than one integer number.

## Permutation of the fixed length

We can calculate the permutation of the constant size set the place we only take a special wide variety of each aspect permutation. Let’s apprehend the following example.

Example –

```
from itertools import permutations
seq = permutations(['H', 'e', 'l', 'l', 'o'], 3)
for p in list(seq):
print(p)
```

Output:

```
('H', 'e')
('H', 'l')
('H', 'l')
('H', 'o')
('e', 'H')
('e', 'l')
('e', 'l')
('e', 'o')
('l', 'H')
('l', 'e')
('l', 'l')
('l', 'o')
('l', 'H')
('l', 'e')
('l', 'l')
('l', 'o')
('o', 'H')
('o', 'e')
('o', 'l')
('o', 'l')
```

In the above code, we have calculated the fixed permutation with the aid of passing length as two.

## Combination of String

Combination is a collection of the factor where the order doesn’t matter. Python itertools module affords the combination() approach to calculate the aggregate of given data. We can calculate the aggregate of a string. Let’s understand the following example.

Example –

```
import itertools
seq = "ABC"
com_seq = itertools.combinations(seq, 2)
for c in com_seq:
print(c)
```

Output:

```
('A', 'B')
('A', 'C')
('B', 'C')
```

## Combination with Replacement

The itertools module consists of some other approach known as combination_with_replacement() which takes underneath consideration the mixture of a quantity itself as well. Let’s apprehend its example.

Combination of Numeric Set

```
from itertools import combinations_with_replacement
com = combinations_with_replacement(['J', 'a', 'v', 'a', 't', 'p', 'o', 'i', 'n', 't'], 2)
#Print the list of combinations
for c in list(com):
print(c)
```

Output:

```
('J', 'J')
('J', 'a')
('J', 'v')
('J', 'a')
('J', 't')
('J', 'p')
('J', 'o')
('J', 'i')
('J', 'n')
('J', 't')
('a', 'a')
('a', 'v')
('a', 'a')
('a', 't')
('a', 'p')
('a', 'o')
('a', 'i')
('a', 'n')
('a', 't')
('v', 'v')
('v', 'a')
('v', 't')
('v', 'p')
('v', 'o')
('v', 'i')
('v', 'n')
('v', 't')
('a', 'a')
('a', 't')
('a', 'p')
('a', 'o')
('a', 'i')
('a', 'n')
('a', 't')
('t', 't')
('t', 'p')
('t', 'o')
('t', 'i')
('t', 'n')
('t', 't')
('p', 'p')
('p', 'o')
('p', 'i')
('p', 'n')
('p', 't')
('o', 'o')
('o', 'i')
('o', 'n')
('o', 't')
('i', 'i')
('i', 'n')
('i', 't')
('n', 'n')
('n', 't')
('t', 't')
```

## Combination of Numeric Set

If the given input is in the sorted order, the combination tuples will be returned in sorted order. Let’s recognize the following example.

Example –

```
import itertools
v = [1, 2, 3, 4]
com_seq = itertools.combinations_with_replacement(v, 3)
for i in com_seq:
print(i)
```

Output:

```
(1, 1, 1)
(1, 1, 2)
(1, 1, 3)
(1, 1, 4)
(1, 2, 2)
(1, 2, 3)
(1, 2, 4)
(1, 3, 3)
(1, 3, 4)
(1, 4, 4)
(2, 2, 2)
(2, 2, 3)
(2, 2, 4)
(2, 3, 3)
(2, 3, 4)
(2, 4, 4)
(3, 3, 3)
(3, 3, 4)
(3, 4, 4)
(4, 4, 4)
```

In this tutorial, we have mentioned the itertools module to locate the permutation and combination of the given statistics using the Python script.

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