Question: Result<T, E>.as_ref() will convert it to Result<&T, &E>, but the expected result is Result<&T, E>. Answer: If you want to place conversion in a function, the function will have to take the Result by reference. This is because, in ...
Question: Result<T, E>.as_ref() will convert it to Result<&T, &E>, but the expected result is Result<&T, E>. Answer: If you want to place conversion in a function, the function will have to take the Result by reference. This is because, in ...